(Back) PayTM Loot – Pay Rs.1 & Get Rs.6 Cashback

Pay Rs.1 & Get Rs.20 Cashback (+ Voucher)

Free PayTM Cash Loot , PayTM 1 ka 20 Offer – Hi Guys , Hope You guys Are Enjoying Our Super Duper Free Recharge Tricks & Free Recharge apps. Yesterday We have Published The Free Rs.10 Paytm cash Loot. I Think Most Of Us have Looted it.

Here is Another Small Loot From PayTM. If You are Old Reader of trickybabaji Then You Must Remembers The Golden Age Of Paytm 5 ka 10 Loots. Paytm Was Giving Free Rs.10 back on Rs.5 Unlimited Time & Most Of us Have Looted it.

Here is Another Similar Kind Of Offer PayTM is Giving Free Rs.20 Cashback On Purchase Of  Cashback Voucher In Rs.1. Means You Will Get Free Rs.19 PayTM Cash + discount Voucher.

How To Get Free Rs.10 Cashback From PayTM On Rs.1 Deals

1} First Of All Just Open This Offer Link In PayTM App Only

Offer Page 

Trick – If You have Used MEGA20 , MEGA40 In PayTM Then Purchase This Deal In PayTM Mall , You Will Get Cashback

2} Now Just Purchase Any Rs.1 Deal Showing On Offer Page

3} Select & Apply The Promocode – MAGIC

PayTM Loot - Buy Deal Of Rs.1 & Get Rs.10 Cashback (New Code)


4} You Will Instantly Get Rs.20 Cash back In Your Wallet

5} Or Cashback Will Be Credited In Your Wallet Within 48 Hours

6} Apart From Free PayTM Cash You Will Receive Vouchers Of Specific Deals , Which Can Be Redeemed On Offline Store For Purchase

7} Best Deal !! Isn’t it ?

8} Enjoy !!

More Details :

  • Cashback will not be processed for non-KYC users. If you have not completed your KYC, you will receive Goldback (inclusive of 3% GST)
  • This cash back offer is being extended by One97 Communications Limited for using your Paytm Wallet. Paytm Wallet can be used for all transactions including shopping, recharges, utility bill payments, movie tickets, travel bookings and payments at stores accepting Paytm as a payment mode.
  • Promo codes are subject to maximum cash back amounts
  • Cash back received will be credited to your Paytm Wallet
  1. Get Rs.200 Cashback on Adding Rs.400.

  2. Bhai maximum time problem

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